Edit Distance
Leetcode https://leetcode.cn/problems/edit-distance/
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
class Solution {
public int minDistance(String word1, String word2) {
if (word1 == null || word2 == null) {
return -1;
}
int word1len = word1.length();
int word2len = word2.length();
int[][] distance = new int[word1len + 1][word2len + 1];
for (int i = 0; i <= word1len; i++) {
for (int j = 0; j <= word2len; j++) {
if (i == 0) {
distance[i][j] = j;
} else if (j == 0) {
distance[i][j] = i;
} else if (word1.charAt(i - 1) == word2.charAt(j - 1)) {
distance[i][j] = distance[i - 1][j - 1];
} else {
distance[i][j] = Math.min(distance[i - 1][j - 1] + 1, distance[i - 1][j] + 1);
distance[i][j] = Math.min(distance[i][j], distance[i][j - 1] + 1);
}
}
}
return distance[word1len][word2len];
}
}
Complexity
- Time = O(m*n)
- Space = O(m*n)
This post is licensed under CC BY 4.0 by the author.